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CSE 331/503 Solved
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Computer Organization Final Project – MiniMIPS Design
In this assignment you will design a small version of MIPS processor. Its name is MiniMIPS. In MiniMIPS, there are 8 registers each holding 32 bit numbers. The instruction width is 16 bits instead of 32 bits in MIPS. There are two types of instructions in MiniMIPS.
R’-type:
Op (4bits) Rs (3bits) Rt (3bits) Rd(3bits) Func(3bits)

I’-type:
Op (4bits) Rs (3bits) Rt (3bits) Imm (10bits)

The instructions of MiniMIPS are given in below table:
Instr Opcode Func
AND 0000 000
ADD 0000 001
SUB 0000 010
XOR 0000 011
NOR 0000 100
OR 0000 101
ADDI 0001 XXX
ANDI 0010 XXX
ORI 0011 XXX
NORI 0100 XXX
BEQ 0101 XXX
BNE 0110 XXX
SLTI 0111 XXX
LW 1000 XXX
SW 1001 XXX

They all work similar to the actual MIPS Green Sheet. As immediate field is 10 bits you should extend it to 32 bits. Do not forget, only the instruction width and number of registers are different remaining part is same as MIPS. The register contents are 32 bits. Zero register is always 0. All other rules in MIPS are also rules of MiniMIPS.

Submission Rules:
• Platform: Teams CSE 331 page
• For late submission: -20pt for each day, end of the 5 days submission will be closed.
o Submission format must be as follows:
o StudentNo.zip -> StudentNo (folder) -> StudentNo.qar, Report_StudentNo.pdf

Report file must be include:
• You need to write a testbench module and show testbench results for each module with SS.
• For MiniMIPS part, you need to try at least two different numbers for all operations
(OpCode:0000 x1+x2 result= , …, OpCode =1001 x1|x2 resut=…, OpCode:0000 x3+x4 result= , …, OpCode =1001 x3|x4 resut=…)
• Explain if you have missing parts, bonus parts or adding parts.
• 2-3 pages will suffice

Design & Codes Rules:
• You will use Structural or Dataflow Verilog.
• Behavioral Verilog is not allowed other than memory components. Only register and memory modules can use behavioral Verilog because of register assignment.
• For testbench structure, please follow DraftForHW4.qar project.

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