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CS220 – THREE BIT ODD PARITY BIT GENERATOR Solved
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Description

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STATE DIAGRAM
Our state machine has 2 states :
● EVEN (1)
● ODD (0)

TRUTH TABLE

EXCITATION TABLE
INPUT BIT (at time t) PRESENT STATE(PS) NEXT STATE (NS) OUTPUT (O/P )
0 0 (ODD) 0 (ODD) 1
0 1 (EVEN) 1 (EVEN) 0
1 0 (ODD) 1 (EVEN) 0
1 1 (EVEN) 0 (ODD) 1
STATE TABLE
PRESENT STATE (P) (NEXT STATE, OUTPUT )
INPUT BIT
0 1
0 (ODD) (0 , 0) (1 ,1)
1 (EVEN) (1 , 1) (0 , 0)
TRANSITION TABLE
PRESENT STATE NEXT STATE
INPUT BIT
0 1
0 (ODD) 0 1
1 (EVEN) 1 0
OUTPUT TABLE
PRESENT STATE OUTPUT
INPUT BIT
0 1
0 (ODD) 0 1
1 (EVEN) 1 0
K-MAP
● FOR NEXT STATE (Y(t+1))
INPUT BIT (X) PRESENT STATE(Y(t))
0 1
0 0 1
1 1 0

𝑌 ( 𝑡 + 1 ) = ( 𝑋 . 𝑌 ( 𝑡 ) ) + ( 𝑋 . 𝑌 ( 𝑡) )
𝑌 ( 𝑡 + 1 ) = 𝑋 ⊕ 𝑌 ( 𝑡 )
● FOR OUTPUT LOGIC (Z)
INPUT BIT (X) PRESENT STATE(Y(t))
0 1
0 0 1
1 1 0

𝑍 = 𝑍 ( 𝑋 =. 𝑌 𝑋( 𝑡 )⊕) + 𝑌 ( 𝑡 () 𝑋 . 𝑌 ( 𝑡 ))
LOGIC DIAGRAM

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