Description

Qadis Chaudhry
Exercise 1
Exercise 1:
==================== Rutgers!
Have a great semester! Hello Scarlet Knights!
2. For the for loop, there is an inherent flaw with how the iteration is defined, and that is the fact that if v1 is greater than a, the loop will run forever. Since the loop subtracts 1 from a for each iteration, and the condition is true if v1 is greater than a, v1 will always be greater than a. The condition for the loop will always be true and it will run forever. Any value of v1 that is greater than 5 will cause this issue since a = 5.
Exercise 2
count = 6, Have a wonderful day.
1. The output of the program is shown above. In this code three variables are defined,i, p and count. Here, the variable p is set to be pointer to count and this means that changing the value of *p will change the value of count. When we reach the for loop, this concept is important since both *p and count are being changed. This means at every iteration the value of count changes twice leaving the final value being 6 over the three iterations.
2. The command to set a breakpoint at a line is simply break and then the name of the file and the line number. To specify a breakpoint at line 7 in the file main.c, the command would be break main.c:7.
3. The break… if expr command might be useful for when dealing with loops and we need to break conditionally at a value of a specific variable. There can be cases where a loop runs and there is a bug within the loop causing some variable to manifest a value that it is not supposed to. If for example we know the desired value, we can have the condition be if not(desired value) and therefore the code will stop at the point where the variable takes on the erroneous value.
Exercise 3
Checking first list for cycles. There should be none, ll has cycle says it has no cycle
1. The output of the program initially is a bunch of errors referring to the printf statements. After the bugs are fixed, this is the intended output of the program, shown above.
2. The bug/fault of this program was the format of the printf statements. Since they spanned two lines, there was no quotation mark to end the argument of the printed statement. To fix the program, we simply needed to add a set of two quotations, one at the end of the first line where it splits and another where the second line begins. Another fix is to make the print argument only span one line and the code will run properly.
Exercise 4
Exercise 5
C code:
#include <stdio.h>
void swap(int *x, int *y) { int temp; temp = *x; *x = *y; *y = temp; return;
}
int main() { int arr[6] = {12, 100, 10, 1000, 11, 12}; int size = sizeof arr / 4; int *p1 = &arr[0]; int *p2 = &arr[size-1]; printf(“Orignial Array: “); for (int i=0; i < size; i++) { printf(“%d “, arr[i]);
} printf(” “);
for (int i=0; i < size / 2; i++) { swap(p1, p2); p1++; p2–;
} printf(“Reversed Array: “); for (int i=0; i < size; i++) { printf(“%d “, arr[i]);
} printf(” “); return 0; }
Output:
Orignial Array: 12 100 10 1000 11 12
Reversed Array:
12 11 1000 10 100 12