Description

This problem is a programming version of Problem 38 from projecteuler.net
Take the number 192 and multiply it by each of 1, 2, and 3:
192 × 1 = 192
192 × 2 = 384
192 × 3 = 576
By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of
192 and (1,2,3)
The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5). Let’s call 9 as the Multiplier M
The similar process can be shown for 1 to 8 pandigital also. 18 when multiplied by 1,2,3,4 gives 18365472 which is 1 − 8 pandigital.
You are given N and K where K = 8 or 9, find the multipliers for that given K below N and print them in ascending order.
Input Format
Input contains two integer N and K.
Output Format
Print the answer corresponding to the test case.
Constraints
100 ≤ N ≤ 105
8 ≤ K ≤ 9
1 < M
Sample Input

Sample Output